Unboxing
When you call a method that wants a boolean
but give it a Boolean
, Java has to unbox the value. This happens automatically and implicitly.
Therefore, during compilation, Java replaces your call
foo(value);
by
foo(value.booleanValue());
This process is explained in detail in JLS, chapter 5.1.8. Unboxing Conversion:
At run time, unboxing conversion proceeds as follows:
- If
r
is a reference of typeBoolean
, then unboxing conversion convertsr
intor.booleanValue()
Unboxing null
Now, when value
is null
, this statement obviously leads to a NullPointerException
at runtime, since you are trying to call a method (booleanValue
) on a variable that does not refer to any instance.
So your code crashes, it will not use any default value as fallback. Java was designed with fail-fast in mind.
Get false
instead
In case you want the method to receive false
as fallback value, you have to code this explicitly yourself. For example by:
foo(value == null ? false : value);
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solved Passing Boolean to method that expects boolean [closed]