[Solved] Need Java Code/Logic to extract COMP. field from EBCDIC file

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I do not use Java, but I will try to explain what is happening.

The value 8188 is 0x1ff8 in big-endian hex. When your program is run the result is actually 8188 - 65536 = -57348. That is why you got the result you did.

Because the input is big-endian binary, only the first bit of b[0] should be checked for a sign. What I did in C# was,

    public static String GetBinary(byte[] b, int decimalPointLocation)
    {
        long val = 0;
        if ((b[0] & 0x80) != 0)
        {
            val = -1;
        }
        for (int i = 0; i < b.Length; i++)
        {
                val = (val << 8) + b[i];
        }
        string s = Convert.ToString(val);
        return s;
    }

For byte[] b = {0x1f, 0xfc} the value returned is 8188. For byte[] b = {0xe0, 0x04} the value returned is -8188.

While I did use similar substring manipulation to insert a decimal point for those values, you need to be aware that absolute integer values less than 100 cannot be properly formatted for two decimal places with that method.

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solved Need Java Code/Logic to extract COMP. field from EBCDIC file