Best way I think
double NthRoot(double value, double degree)
{
return pow(value, (double)(1 / degree));
}
From here.
0
solved n-th root of a number [closed]
Best way I think
double NthRoot(double value, double degree)
{
return pow(value, (double)(1 / degree));
}
From here.
0
solved n-th root of a number [closed]