[Solved] myfile.open isn’t working correctly and cout does not show data

Question

The open method of an input file stream requires the second parameter. Try changing the line:

myfile.open("potentials.txt");

to

myfile.open("potentials.txt", std::ifstream::in);

EDIT: Or just open the file when you declare myfile like so:

ifstream myfile("potentials.txt");

If this still isn’t working, you are likely not opening the file correctly. E.g. wrong directory. Use a full path to the file.

Accepted Answer

The open method of an input file stream requires the second parameter. Try changing the line:

myfile.open("potentials.txt");

to

myfile.open("potentials.txt", std::ifstream::in);

EDIT: Or just open the file when you declare myfile like so:

ifstream myfile("potentials.txt");

If this still isn’t working, you are likely not opening the file correctly. E.g. wrong directory. Use a full path to the file.