public static void main(String[] args) {
int smallest = 0;
int large = 0;
int num;
System.out.println("enter the number");//how many number you want to enter
Scanner input = new Scanner(System.in);
int n = input.nextInt();
num = input.nextInt();
smallest = num; //assume first entered number as small one
// i starts from 2 because we already took one num value
for (int i = 2; i < n; i++) {
num = input.nextInt();
//comparing each time entered number with large one
if (num > large) {
large = num;
}
//comparing each time entered number with smallest one
if (num < smallest) {
smallest = num;
}
}
System.out.println("the largest is:" + large);
System.out.println("Smallest no is : " + smallest);
}
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solved Java program to find the largest & smallest number in n numbers without using arrays