[Solved] INT_MAX divided by twice of itself (INT_MAX * 2)

by


What you are trying is impossible for 2 reasons.

First, INT_MAX + INT_MAX cannot be represented by an int, which is logical since the maximum value of an int is INT_MAX. This leads to an overflow.

Second, even if you try to do (3 / (3 + 3)) you will get 0 since you are working with integers and not fractional numbers. Do do what you want to do you can try:

static_cast<double>(INT_MAX) / (static_cast<double>(INT_MAX) + static_cast<double>(INT_MAX)) though this has no interest.

9

solved INT_MAX divided by twice of itself (INT_MAX * 2)