[Solved] in C programming, how to print 1 character [closed]

Question

 scanf_s("%d", &d);

This reads characters as long as they fit the "%d" format. The first character not fitting that format is the newline you entered. This remains in the input stream.

 scanf_s("%f", &f);

This skips leading whitespaces (i.e., your newline), then reads characters as long as they fit the "%f" format. The first character not fitting that format is the newline you entered. This remains in the input stream.

 scanf_s("%c", &c);

This reads one character from the input without skipping potential leading whitespace, i.e., your newline.

It also is undefined behaviour: One thing that scanf_s() does differently than standard scanf() is that it demands a “buffer size” numerical parameter for %c and %s, to avoid buffer overflow. Not giving that parameter makes scanf_s() pull an integer from the stack where you didn’t put one, resulting in undefined behaviour. If that next memory address happens to be zero, you’ll be scratching your head a lot I would bet…

Accepted Answer

 scanf_s("%d", &d);

This reads characters as long as they fit the "%d" format. The first character not fitting that format is the newline you entered. This remains in the input stream.

 scanf_s("%f", &f);

This skips leading whitespaces (i.e., your newline), then reads characters as long as they fit the "%f" format. The first character not fitting that format is the newline you entered. This remains in the input stream.

 scanf_s("%c", &c);

This reads one character from the input without skipping potential leading whitespace, i.e., your newline.

It also is undefined behaviour: One thing that scanf_s() does differently than standard scanf() is that it demands a “buffer size” numerical parameter for %c and %s, to avoid buffer overflow. Not giving that parameter makes scanf_s() pull an integer from the stack where you didn’t put one, resulting in undefined behaviour. If that next memory address happens to be zero, you’ll be scratching your head a lot I would bet…