A RegExp solution would use positive lookaheads (?=pattern)
to make sure the sequence is in the correct part of the String
You need to match 1 or 2 \d
(digits) where
- It is followed by zero or more groups of 2 digits
(?:\d{2})*
- Which is followed by a group of 3 digits and the end of the string
\d{3}$
So you’d write a RegExp lke this /(\d\d?)(?=(?:\d{2})*\d{3}$)/
, and in usage
'1234567890'.replace(/(\d\d?)(?=(?:\d{2})*\d{3}$)/g, '$1,');
// "1,23,45,67,890"
0
solved I want to seperate the entered string as indian money format like if i entered 123456 means, then i want to get 1,23,456