[Solved] I couldn’t make this programm run as I wanted

Question

Your code has few errors. From

Usage: java Phone

it looks like expected content of args array should be "Phone" <name> which are two elements so

if(args.length != 1)

is not valid condition. You probably should replace it with

if (args.length < 2)

Other problem is that <name> is second element in args array stored in args[1] so

if(numbers[i][0].equals(args[0]))

should be

if(numbers[i][0].equals(args[1])) //we want to compare name, not "Phone" string

Last problems involve

if (i == numbers.length);
    System.out.println("Name not found.");

inside for loop i will never be equal number.length because for (i = 0; i < numbers.length; i++) loop iterates only if i<number.length. So this condition should be replaced with
```
if (i == numbers.length -1)
```
there is semicolon right after this condition which represents empty instruction, which means that
```
if (i == numbers.length - 1);
    System.out.println("Name not found.");
```
is essentially same as
```
if (i == numbers.length - 1)
    ;
System.out.println("Name not found.");
```
which means that execution of System.out.println("Name not found."); doesn’t depend on result of if condition.

To solve this problem simply remove this additional ;, and to avoid this problem always surround code which should depend of if else for while inside blocks {...}.

Accepted Answer