[Solved] I can’t run this code of coverting an array into a list

Question

Your definition for the array is incorrect, it should be:

int t[n];

Note that you do not need to declare a local array for your purpose, but you should check for proper conversion by scanf.

Note also that insert_end probably does not take a list *** argument.

Here is an improved version:

void tab2list(int n, list **T) {
    int i, res, value;
    for (i = 0; i < n;) {
        printf("Entrez l'element %d du tableau\n", i + 1);
        res = scanf("%d", &value);
        if (res == 1) {
            insert_end(value, T);
            i++;
        } else 
        if (res == -1) {
            printf("fin de fichier inattendue\n");
            break;
        } else {
            scanf("%*s"); /* skip the offending input */
        }
    }
}

If you need to perform some extra checks on the values before inserting them into the list, you can split the code in 2 loops:

void tab2list(int n, list **T) {
    int i, res, t[n];
    for (i = 0; i < n;) {
        printf("Entrez l'element %d du tableau\n", i + 1);
        res = scanf("%d", &t[i]);
        if (res == 1) {
            i++;
        } else 
        if (res == -1) {
            printf("fin de fichier inattendue\n");
            return;
        } else {
            scanf("%*s"); /* skip the offending input and try again */
        }
    }
    /* perform some extra checks on the array... */
    for (i = 0; i < n; i++) {
        insert_end(t[i], &T);
    }
}

EDIT after you gave further information on your actual problem, here is a fixed version:

#define z 50
struct list {
    int val;
    struct list *next;
};
typedef struct list list;

void tab2list(int *t, int n, list **T) {
     int i;
     for (i = 0; i < n; i++) {
         insert_end(t[i], T);
     }
}

int main(void) {
    int n, i;
    int t[z];
    list *tete = NULL;
    printf("Entrez le nb d'element de ton tableau(max 50)\n");
    scanf("%d", &n);
    for (i = 0; i < n; i++) {
        printf("Entrez l'element %d du tableau\n", i + 1);
        scanf("%d", &t[i]);
    }
    tab2list(t, n, &tete);
    afficher_list(tete);
    return 0;
}

Accepted Answer