[Solved] How to form a dynamic array in C++?

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Use std::vector, which is designed for exactly this use case.

The (rough) translation of the Perl code you have given to C++ using std::vector would be something like this:

#include <iostream>
#include <vector>

int main() {
    // Declare a vector that can only contain int values.
    std::vector<int> numbers;

    // Put the numbers [1,10] into the array.
    for (int i = 1; i <= 10; ++i) {
        numbers.push_back(i);
    }

    // Display the contents of the vector.
    for (auto const &values : numbers) { std::cout << values << '\n'; }

    return 0;
}

(Live demo)

If you do not need the container allocations to be contiguous, std::deque might perform better under certain access/modification patterns, as it makes multiple allocations and therefore does not require that the existing contents be copied when the container runs out of capacity.

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solved How to form a dynamic array in C++?