[Solved] How to create a file with filename as key of dictionary

by


You may open k and not 'k'

imports = ["import json", "import defaultdict"]
d = {'1': 'print ("This is test file")', '2': 'print ("This is test file")'}
for k, v in d.items():
    with open(k + ".py", 'w') as fr:
        for imp in imports:
            fr.write(imp + "\n")
        fr.write(v)

solved How to create a file with filename as key of dictionary