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The expression "cake" || "Cake" evaluates to true, because both those strings are truthy. So when user’s input is compared with that value, for example "cake" == true, it evaluates to true because the user’s input ("cake") is also truthy.
To ignore the case of user’s input, you can simply convert it to lowercase (by make.toLowerCase()) before comparing:
var make = prompt("Hey! What you are up to cake or pancake?");
switch (make.toLowerCase()) {
case "cake":
console.log("Okay! Great choice We are working hard for your cake");
break;
case "pancake":
console.log("Okay! Great choice We are working hard for your pancake");
break;
default:
console.log("Sorry we Only have cake or pancake to choose from.");
}If you are not familiar with the concept of truthy or falsy values, you can read MDN’s documentation here: https://developer.mozilla.org/en-US/docs/Glossary/Truthy & https://developer.mozilla.org/en-US/docs/Glossary/falsy
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solved How to convert upper case to lowercase stored in a variable inside switch statment [duplicate]