[Solved] How to convert an char array (like {1-345}) into an Int array

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I am using the simple approach of type casting from character to integer as,
N[i] = (int)s[i] -‘0’;

Here N is integer array , s is the character array .I simply type cast the character array into integer , it will treat it as a ASCII code of s[i]. so I minus the ‘0’ character (this show the number must be in original value not in ascii code).

You can try the below code!
Also I am attaching the screenshot of the output of code.

#include<stdio.h>
#include<conio.h>
#include<iostream>
using namespace std;
int main()
{
    //character array 's' with length of 5
    char s[5] = { '1', '3', '2', '5', '6' };

    //before converting , prints the character array
    cout << "\t\tCharacter Array" <<endl;
    for (int i = 0; i < 5; i++)
    {
        cout << s[i] << "\t";
    }

    //integer array 'N' with length of 5
    int N[5];
    cout << "\n\tConverting Character Array to Integer Array" << endl;
    //convert the character array into integer type and assigning the value into integer array 'N'
    for (int i = 0; i < 5; i++)
    {
        N[i] = (int)s[i] - '0';
    }


    cout << "\t\tInteger Array" << endl;
    //after converting , prints the integer array
    for (int i = 0; i < 5; i++)
    {
        cout <<N[i]<<"\t";
    }

    _getch();
    return 0;
}

Output of the code

1

solved How to convert an char array (like {1-345}) into an Int array