[Solved] How to add each elements of two unequal arrays and store it in third array? [closed]

by


Despite your bad explanation, i think this is what you are looking for.

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a[] = {1, 2, 3};
    int b[] = {1, 2};

    int numElementsA = sizeof(a) / sizeof(int);
    int numElementsB = sizeof(b) / sizeof(int);

    int finalSize = numElementsA * numElementsB;
    printf("finalSize: %i\n", finalSize);

    int* c = malloc(finalSize * sizeof(int));
    int cc = 0;

    for (int x = 0; x < numElementsA; x++) {
        for (int y = 0; y < numElementsB; y++) {
            c[cc] = a[x] + b[y];
            cc++;
        }
    }

    for (int i = 0; i < finalSize; i++) {
        printf("%i ,", c[i]);
    }

    //make sure memory doesn't leak
    free(c);

    return 0;
}

Output:

finalSize: 6
2, 3, 3, 4, 4, 5,

4

solved How to add each elements of two unequal arrays and store it in third array? [closed]