[Solved] How do print the following pattern in C/C++?

by


Here is an approach :

int cur=1,num=1;
for(int i=0;i<4;i++)
{
    for(int j=0;j<cur;j++)
    {
        if(j!=0)
          printf("*");
        printf("%d",num++);
    }
    printf("\n");
    cur++;
}
cur=4,num=10;
for(int i=0;i<4;i++)
{
    int temp=num-cur+1;
    for(int j=0;j<cur;j++)
    {
        if(j!=0)
          printf("*");
        printf("%d",temp++);
    }
    printf("\n");
    num-=cur;
    cur--;
}

solved How do print the following pattern in C/C++?