You can use the partition
method for this. It’s part of the built-in str
type.
>>> help(str.partition)
partition(self, sep, /)
Partition the string into three parts using the given separator.
This will search for the separator in the string. If the separator is found,
returns a 3-tuple containing the part before the separator, the separator
itself, and the part after it.
If the separator is not found, returns a 3-tuple containing the original string
and two empty strings.
If you use "AWB No: "
as the separator, you’ll get back a 3-tuple containing:
- everything before
"AWB No: "
e.g."Courier "
- the separator:
"AWB No: "
- everything after
"AWB No: "
:"56454546"
So you can get that “everything after” part in two ways:
input_str = "Courier AWB No: 56454546"
sep = "AWB No: "
before, sep, after = input_str.partition(sep)
# == "Courier ", "AWB No: ", "56454546"
# or
after = input_str.partition(sep)[2]
# either way: after == "56454546"
If there are more words after the number you can get rid of them with .split()[0]
:
input_str = "Courier AWB No: 56454546 correct horse battery staple"
sep = "AWB No: "
after = input_str.partition(sep)[2]
awb_no = after.split()[0]
# after == "56454546"
Or in one line:
input_str = "Courier AWB No: 56454546 correct horse battery staple"
awb_no = input_str.partition("AWB No: ")[2].split()[0]
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solved How do I select random text on screen [closed]