[Solved] how can I square the numbers between 0 and any input with extremely large numbers in python [closed]

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If I am interpreting your question correctly, you simply need to devise a very simple list comprehension program.

Getting the square root of everything between zero and n is not necessary. Did you mean square?

Here’s my solution:

def nbDig(n,d):
    int_list = str([str(x*x) for x in range(0,n+1)]).count(str(d))
    return int_list

I can test it like so:

nbDig(12,1)

This returns 7.

EDIT: I didn’t realize calling .replace was totally unnecessary. Thanks for the feedback!

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solved how can I square the numbers between 0 and any input with extremely large numbers in python [closed]