[Solved] How can I decode an NSString using the A1Z26 cipher? [closed]

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In Objective C this can be done as follows:

-(NSString *)decode:(NSString *)input {
    NSArray<NSString *> *components = [input componentsSeparatedByString:@"-"];
    NSMutableString *output = [[NSMutableString alloc] init];
    for (NSString *component in components) {
        if (component.length == 0) {
            continue;
        }
        char charValue = (char) [component intValue];
        [output appendFormat:@"%c", charValue + ('a' - 1)];
    }
    return [NSString stringWithString:output];
}

Note that this assumes the input already has the correct format. It will accept strings of the form "--42-df-w---wf" happily.

EDIT: If there are multiple possible separators (e.g. hyphen and space), you can use NSCharacterSet:

-(NSString *)decode:(NSString *)input {
    NSCharacterSet *separatorSet = [NSCharacterSet characterSetWithCharactersInString: @"- "];
    NSArray<NSString *> *components = [input componentsSeparatedByCharactersInSet:separatorSet];
    ...
}

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solved How can I decode an NSString using the A1Z26 cipher? [closed]