[Solved] How can i compare three strings using only one pointer and nothing else

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I want to have a program in C that reads 3 numbers and prints the bigger one, using only one pointer and no more variables.

#include <stdio.h>
#include <stdlib.h>
int main(void)
{
    int *p;
    p = malloc(sizeof *p); // assume it worked
    if (scanf("%d", p) != 1) /* error */; // read 1st number
    printf("%d\n", *p); // print 1st number
    if (scanf("%d", p) != 1) /* error */; // read 2nd number
    printf("%d\n", *p); // print 2nd number
    if (scanf("%d", p) != 1) /* error */; // read 3rd number
    printf("%d\n", *p); // print 3rd number
    free(p);
}

The program above, does what is required. In addition it prints the middle and smaller numbers!

Update using array of 3 pointers

#include <stdio.h>
#include <stdlib.h>
int main(void)
{
    int *p[3];
    p[0] = malloc(sizeof *p[0]); // assume it worked
    p[1] = malloc(sizeof *p[0]); // assume it worked
    p[2] = malloc(sizeof *p[0]); // assume it worked
    if (scanf("%d", p[0]) != 1) /* error */; // read 1st number
    if (scanf("%d", p[1]) != 1) /* error */; // read 2nd number
    if (scanf("%d", p[2]) != 1) /* error */; // read 3rd number
    if ((*p[0] >= *p[1]) && (*p[0] >= *p[2])) printf("%d\n", *p[0]);
    if ((*p[1] > *p[0]) && (*p[1] >= *p[2])) printf("%d\n", *p[1]);
    if ((*p[2] > *p[0]) && (*p[2] > *p[1])) printf("%d\n", *p[2]);
    free(p[2]);
    free(p[1]);
    free(p[0]);
}

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solved How can i compare three strings using only one pointer and nothing else