[Solved] Finding the last digit of a very large 2^n number [closed]

Powers of 2:

2, 4, 8, 16, 32, 64, 128, 256...

Last digits:

2, 4, 8, 6, 2, 4, 8, 6...

Last digit of 2^i is:

int arr[4] = {2, 4, 8, 6};
return arr[(i-1)%4];