[Solved] Finding largest square less than a given number in Java [closed]

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Here is how to do this with loops

int n=10; //This is your Number
int i = 0;
for(i=n;i>=1;i--)
    if((int)Math.sqrt(i)*(int)Math.sqrt(i)==i)
        break;
System.out.println(i);

Below is how it works:-

The Loop runs from the n, which is your number, to 1. It then checks whether, the square root of i, which is running through n to 1, is a perfect square. If it is, it breaks the loop, and prints the value of i on the screen.

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solved Finding largest square less than a given number in Java [closed]