[Solved] Find loop value inside string


This works.

#include <string>
#include <iostream>
using namespace std;
int main()   {  
char title[20] = "testmovie2015.mkv";
int year=0,i=0;
for(i=0;title[i]!='\0';i++){
if(isdigit(title[i])&&isdigit(title[i+1])&&isdigit(title[i+2])&&isdigit(title[i+3]))
{   year=1;
    break; 
}
                    }
if(year)
{
 year=((title[i]-'0')*1000)+((title[i+1]-'0')*100)+((title[i+2]-'0')*10)+(title[i+3]-'0');
 if(year>=2000&&year<=2018)
 {   int k=0;
     while(k<i)
     {   
         cout<<title[k];
         k++;
     }
 }
 else
 {
     cout<<"Year found: "<<year<<", but out of given range";
 }
}
else
{
    cout<<"No year found in the string";
}

        }

3

solved Find loop value inside string