[Solved] Enable MVVM object only if three other MVVM objects are already enable

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you could use this:

 //Button B
        private bool _enableButtonB;
        public bool EnableButtonB
        {
            get
            {
                return _enableButtonB;
            }
            set
            {
                _enableButtonB = value;
                OnPropertyChanged("EnableButtonB");
              EnableButtonA=value;
            }
        }
private bool _enableButtonC;
        public bool EnableButtonC
        {
            get
            {
                return _enableButtonC;
            }
            set
            {
                _enableButtonC = value;
                OnPropertyChanged("EnableButtonC");
               EnableButtonA=value;
            }
        }

        //Button D
        private bool _enableButtonD;
        public bool EnableButtonD
        {
            get
            {
                return _enableButtonD;
            }
            set
            {
                _enableButtonD = value;
                OnPropertyChanged("EnableButtonD");
                 EnableButtonA=value;
            }
        }

        //Button A - What I tried so far
        private bool _enableButtonA;
        public bool EnableButtonA
        {
            get
            {
                var enable=EnableButtonB & EnableButtonC & EnableButtonD;
                if(enable!=_enableButtonA) _enableButtonA=enable;
                return _enableButtonA;
            }
            set
            {
                if(!value) _enableButtonA=value;

                else
                    _enableButtonA = EnableButtonB & EnableButtonC & EnableButtonD ;
               
                OnPropertyChanged("EnableButtonA");
            }
        }
    }
}

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solved Enable MVVM object only if three other MVVM objects are already enable