What do You mean?
You have to cast f to long and b to char and also initialize them.
l = (long) f;
ch = (char) b;
//----
float f = 3.14f;
long l ;
char ch;
byte b = 38;
l= (long) f;
ch= (char) b;
Check examples:
int first = 3:
int second = 2;
double result = first / second; // the result is 1 because first and second are integers
first = 3;
second = 2;
double result1 = (double)first / second; // result is: 1.5
double result2 = first / (double)second; // result is: 1.5
double result3 = (double)(first / second); // result is: 1
solved Data type conversion [closed]