[Solved] Data inserting in mysql data base not working [closed]

by


response_id,participant_id,question_id,answer_option_answer_text vs

(response_id,participant_id,question_id,answer_option)

and your line ” $participant_id=$_POST[‘participant_id’]
” is missing its semicolon (;)

also please use

if( !mysql_query( $query, $con ) ) { 
echo("Failure: " . mysql_error()  ); 
}

to insert data.

2

solved Data inserting in mysql data base not working [closed]