[Solved] counting the number of zeros [closed]

by


Here you go:

char[] numArray = num.toCharArray();
  int counter=0;
  for(int i=0;i<numArray.length;i++) {
     if(numArray[i]=='0') {
        counter++; 
     }
     if((i==numArray.length-1&&counter>0)||(counter>0&&numArray[i]!='0')) {
        System.out.println("Number of Zeroes: "+counter);
        counter=0;
     }
  }

Some important points:

1) It’s best to use an array of char values here, instead of operating using a double, because a char array can store many more values- the example you posted is too long for a double to handle.

2) Most of this should be self-explanatory (at least, if you study it bit-by-bit), but in case the i==numArray.length-1 part is confusing, this ensures that if the string ends with a 0, the final count of 0’s will be printed out as well.

This should work for any string you can throw at it- including values besides 0 and 1, if you need support for it!

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solved counting the number of zeros [closed]