Here is the not-so-scalable C way.
#include <stdio.h>
int main(void){
int matrix[4][2] = {{1,1},{1,2},{2,1},{2,2}};
int i, j, counter=0;
for (i=0;i<4;i++)
{
if (matrix[i][0] == 1 && matrix[i][1] == 1)
counter++;
}
printf("count %d", counter);
}
0
solved Count the occurences of rows based on it’s columns values