[Solved] convert int to pointer int *ptr position;

by


There are many problems here

z is a local variable int.
its address will not be useful to return, because it will be out of scope.
returning an offset from its address is even worse, since that is a totally unrelated place in memory.

you also have an off-by-one error. imagine Number elements is one. You will then try to view ptr+1 instead of ptr+0.

you’ve also tagged this c++ but are writing c style code.

to answer your primary question, rather than writing ReverResult=(z+rever) one could write *(ReverResult + rever - 1) = *(ptr + i)

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solved convert int to pointer int *ptr position;