[Solved] Conversion not valid from char to const char*

Question

This line is wrong:

keyw(str);

Instead of that you need:

keyw(&str);

The function keyw(char *p) needs a pointer or an address.

Accepted Answer

This line is wrong:

keyw(str);

Instead of that you need:

keyw(&str);

The function keyw(char *p) needs a pointer or an address.