Your formula can be translated like this:
double i = 1;
double sum = 0;
do{
sum += (1/i + 18*i);
i--;
} while (i < 16);
I’m not really sure that using a do while
is the best option, it would probably be better with a for
loop like so:
double sum = 0;
for (double i = 1; i < 16; ++i){
sum += (1/i + 18*i);
}
1
solved Computing a formula using do/while statements [closed]