[Solved] Class has no member speak? [closed]

Question

void::speak(); //THE GLOBAL SCOPE HAS NO SPEAK

It’s interpreting this as void ::speak() where leading an identifier (a name) with :: indicates to C++, “Look in the global scope of all names”. :: is the “scope resolution operator”

In the header file, you should just use void speak(); since C++ sees it inside your class declaration and hence knows it’s part of the class.

Accepted Answer

void::speak(); //THE GLOBAL SCOPE HAS NO SPEAK

It’s interpreting this as void ::speak() where leading an identifier (a name) with :: indicates to C++, “Look in the global scope of all names”. :: is the “scope resolution operator”

In the header file, you should just use void speak(); since C++ sees it inside your class declaration and hence knows it’s part of the class.