This is very crude and it is unclear what you want:
s1 = "t his will fail"
s2 = "t h i s s e p a d"
def is_spaced(s):
prev = s[0]
result = "is spaced"
for c in s[1:]:
if not c.isspace() and not prev.isspace():
result = "not spaced"
break
prev = c
return result
print(is_spaced(s1))
print(is_spaced(s2))
Outputs:
not spaced
is spaced
1
solved Check if a string has space between all its letters [closed]