[Solved] char () and int () are functions in c++? [duplicate]

Question

They’re not functions. They’re just alternate syntax for type-casting. char(x) is more-or-less equivalent to static_cast<char>(x).

In general, in C++, one should prefer the C++-specific constructs for casting objects (static_cast, dynamic_cast, const_cast, and reinterpret_cast), as those help ensure you don’t do anything dumb when casting objects. So in your code example, I’d recommend rewriting it as

result += static_cast<char>(static_cast<int>(text[i]+s-65)%26 +65);

But functionally, it’s all identical.

Accepted Answer

They’re not functions. They’re just alternate syntax for type-casting. char(x) is more-or-less equivalent to static_cast<char>(x).

In general, in C++, one should prefer the C++-specific constructs for casting objects (static_cast, dynamic_cast, const_cast, and reinterpret_cast), as those help ensure you don’t do anything dumb when casting objects. So in your code example, I’d recommend rewriting it as

result += static_cast<char>(static_cast<int>(text[i]+s-65)%26 +65);

But functionally, it’s all identical.