[Solved] C++: Using remove_if to filter vector on a condition

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Below example demonstrates the usage of erase-remove_if. limit is captured by reference and can thus be modified outside the lambda:

#include <vector>
#include <algorithm>
#include <iostream>
int main()
{
    std::vector<int> vec{0,1,2,3,4,5,6,7,8,9};
    int size = vec.size();
    for (int limit = 0; limit <= size; limit++)
    {
        vec.erase(std::remove_if(std::begin(vec), std::end(vec), [&limit](int i) {
            return i < limit;
        }), std::end(vec));
        for (auto& v : vec)
            std::cout << v;
        std::cout << std::endl;
    }
    return 0;
}

Expected output:

0123456789
123456789
23456789
3456789
456789
56789
6789
789
89
9

1

solved C++: Using remove_if to filter vector on a condition