To test if two consecutive numbers are equal, you dont need 100 elements, you need 2:
int points[2], counter = 1;
// Read in first point:
cin >> points[0];
// Read until we meet our condition:
do {
// Read a point into the next part of the array.
cin >> points[counter];
// toggle counter between 0 and 1
counter = (counter + 1) % 2;
// Check if we are done:
} while (points[0] != points[1]);
2
solved C++: Using for loop I need to take infinite values of a point using arrays. How can I take values of point [ ] until 2 points of are equal