[Solved] C++ Multi Switch and Break?

Question

A break statement only breaks the closest switch/loop that it is called in.

In your example, the break statements of the inner switch would only break out of the inner switch, execution would return to case 0 of the other switch. And then, since that case 0 does not have a break of its own, execution would fall through to case 1, which also does not have a break, so execution would fall through to case 4, which does have a break to end the outer switch.

This is certainly true in C and C++, anyway. Not necessarily in other languages. For example, Delphi does not fall-through between case blocks. Break can be used to end a case block early, but it is optional, the block is finished when the end of its scope is reached.

Accepted Answer

A break statement only breaks the closest switch/loop that it is called in.

In your example, the break statements of the inner switch would only break out of the inner switch, execution would return to case 0 of the other switch. And then, since that case 0 does not have a break of its own, execution would fall through to case 1, which also does not have a break, so execution would fall through to case 4, which does have a break to end the outer switch.

This is certainly true in C and C++, anyway. Not necessarily in other languages. For example, Delphi does not fall-through between case blocks. Break can be used to end a case block early, but it is optional, the block is finished when the end of its scope is reached.