Now you can get file names.
Just compare a file name.
while ((dirp = readdir(dp)) != NULL) {
std::string fname = dirp->d_name;
if(fname.find("abc") != std::string::npos)
files.push_back(fname);
}
Also you can use scandir function which can register filter function.
static int filter(const struct dirent* dir_ent)
{
if (!strcmp(dir_ent->d_name, ".") || !strcmp(dir_ent->d_name, "..")) return 0;
std::string fname = dir_ent->d_name;
if (fname.find("abc") == std::string::npos) return 0;
return 1;
}
int main()
{
struct dirent **namelist;
std::vector<std::string> v;
std::vector<std::string>::iterator it;
n = scandir( dir_path , &namelist, *filter, alphasort );
for (int i=0; i<n; i++) {
std::string fname = namelist[i]->d_name;
v.push_back(fname);
free(namelist[i]);
}
free(namelist);
return 0;
}
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solved C++ How to search files in a directory with certain name? [closed]