1/h = 0 and (1/h) += (1/i) don’t work because you’re trying to assign a value the result of an expression, not an object.  It’s like writing 1 = 2 and expecting it to be meaningful; it isn’t.  
You’re trying to solve for h.  So you need to sum 1/1 + 1/2 + 1/3 + ... and take the inverse:
double u = 0.0; // u == 1/h == 1/1 + 1/2 + 1/3 + 1/4 + ...
for ( int i = 1; i <= 1000; i++ )
{
  u += 1.0 / i;
}
printf( "1/h = %f, h = %f\n", u, 1.0/u );
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solved C error: lvalue required as left operand of assignment