[Solved] bash, if then script to parse file [closed]

by


plain bash, though can easily be converted to POSIX sh. 

#!/usr/bin/env bash

in=0 # whether we are inside a 'virtual' block
     # such a block ends once we meet a line that starts with '}'

while read -r
do
    if [[ $REPLY =~ ^virtual ]]; then
        in=1
        echo "${REPLY% *}"
    elif (( in )); then
        if [[ $REPLY =~ ^pool ]]
        then echo "$REPLY"
        elif [[ $REPLY =~ ^destination ]]
        then echo "${REPLY%:*}" # or just "$REPLY" if you want the ':https' part
        elif [[ $REPLY =~ ^} ]]
        then in=0
        fi
    fi
done < file

where file is your data. You can change that to "$1"
and give the file as an argument to the script.

tested with given data, returns:

virtual vs_website_443
pool pl_website_443
destination 11.11.11.11

using plain awk

awk '$1 == "virtual" { f=1; print $1,$2; next }         \
     f == 1 { if ($1 == "pool") { print }               \
              else if ($1 == "destination") { print }   \
              else if ($0 ~ /^}/) { f=0 }               \
     }' file

with the given data output is:

 $ awk '$1 == "virtual" { f=1; print $1,$2; next } f == 1 { if ($1 == "pool") { print } else if ($1 == "destination") { print } else if ($0 ~ /^}/) { f=0 } }' file
virtual vs_website_443
pool pl_website_443
destination 11.11.11.11:https

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solved bash, if then script to parse file [closed]