You can do that in this way, Also; you can specify how many terms you want in between first and last one by the third argument. Use simple mathematics.
def ap(arg1, arg2, d):
diff = arg2 - arg1
for i in range(d): yield arg1 + i*(diff/(d+1)) # division by d+1
>>> list(ap(1, 6, 4))
[1.0, 2.0, 3.0, 4.0, 5.0, 6.0]
solved AP in Python using function