[Solved] Mysql combine link with title

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You did not close tags correctly. Try this, they will be in same column <td><a href=”https://stackoverflow.com/questions/42284211/<?php echo $row[“description’]; ?>”> <?php echo $row[‘post_title’]; ?></a></td> I hope this helps Edit: Also for not underlined link you can use this css attribute: <td><a style=”text-decoration: none;” href=”https://stackoverflow.com/questions/42284211/<?php echo $row[“description’]; ?>”> <?php echo $row[‘post_title’]; ?></a></td> 0 solved Mysql combine link … Read more

[Solved] SELECT statement with if ELSE in SQL Server

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If I understood your question correctly, you want distinct ref number with doc number is the following condition (as per the output shown). If the all the existing doc numbers are same for a ref number, then get max(doc) otherwise sum(doc). SELECT ref, (CASE WHEN MAX(doc) = MIN(doc) THEN MAX(doc) ELSE SUM(doc) END) AS doc … Read more

[Solved] Returning a different type than the parameter

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There is a lot that can be improved in your code, let me add some comments public void add(String candidate){ //if candidate is actually null you are calling null.equals //which means this will always result in a NullPointerException //you can remove this if if you want if (candidate.equals(null)){ throw new RuntimeException(); } … //think about … Read more

[Solved] Warning: implode(): Invalid arguments passed

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There are two possible solutions according to your question & your posted comments: When you want to print only the names of the ‘name’ key element, then place this code: $arr = array(); foreach ($numbers as $key => $value) { if(is_array($value)) { foreach($value as $val){ if($key == ‘name’) { $arr[] = $val; } } } … Read more

[Solved] Print Hexagonal pattern using asterisk [closed]

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To work on arbitrary lengths>1, you have to change the second if-statement. I fixed the last one for you: sideLength = 5 totalLength = (sideLength) + 2*(sideLength-1) loop = 1 while loop<=totalLength : if loop==1 or loop==totalLength: print ” “*(sideLength-1) + “*”* sideLength + ” “*(sideLength-1) if loop>sideLength-1 and loop<= 2*sideLength-1: print “*” + ” … Read more

[Solved] Solving an equation with python

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You can do things like this with the sympy library. http://docs.sympy.org/dev/index.html >>> from sympy import * >>> from sympy.solvers import solve >>> ca, ra = symbols(“ca ra”) >>> eq = -ra + (1.5 * (ca – (ra/2))/(1 + 0.8 * (ca – (ra/2)))) >>> print(eq) -ra + (1.5*ca – 0.75*ra)/(0.8*ca – 0.4*ra + 1) >>> … Read more

[Solved] Where I can find proper guidance to create Add-in for Revit using C#? [closed]

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Your first port of call should definitely be the official Revit Developer Centre: http://www.autodesk.com/developrevit Work through the DevTV and My First Revit Plugin tutorials. That will provide all you need. The Building Coder provides a comprehensive overview of the Revit API getting started material for self-learning: http://thebuildingcoder.typepad.com/blog/about-the-author.html#2 1 solved Where I can find proper guidance … Read more

[Solved] This python code calls a function that returns a value but user input is asked twice [closed]

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Within the function grades you’re asking for the score: score = float(input(“enter the score please”)) and then outside of the function, you’re also doing it: MyScore=float(input(“enter my score”)) Remove one of the two input statements, and it will only ask you the one time 🙂 def grades(score): if score<0.0 or score>1.0: return “Wrong score” elif … Read more

[Solved] Calculate conditional mean in R with dplyr (like group by in SQL) [duplicate]

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I think what you are looking for (if you want to use dplyr) is a combination of the functions group_byand mutate. library(dplyr) city <- c(“a”, “a”, “b”, “b”, “c”) temp <- 1:5 df <- data.frame(city, temp) df %>% group_by(city) %>% mutate(mean(temp)) Which would output: city temp mean(temp) (fctr) (int) (dbl) 1 a 1 1.5 2 … Read more

[Solved] How To configure Hibernate as a JPA provider for Payara/Glassfish 4.1? [closed]

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Found the answer in this article : Hibernate 5 in Payara Briefly, add Hibernate dependencies in your pom.xml, replace payara/glassfish jboss-logging.jar /lib with latest and then restart server. Your project should have in the persistence.xml its provider org.hibernate.jpa.HibernatePersistenceProvider and property name=”hibernate.transaction.jta.platform” value=”org.hibernate.service.jta.platform.internal.SunOneJtaPlatform” solved How To configure Hibernate as a JPA provider for Payara/Glassfish 4.1? [closed]