[Solved] Returning wrong values with if in python in DEF() statement

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If RESULTHAZARD is 2, RESULTHAZARD == 2 or 3 evaluates to True or 3 which evaluates to True. Otherwise, RESULTHAZARD == 2 or 3 evaluates to False or 3 which evaluates to 3, which is a truthy value.

You need to explicitly compare both for equality. Either with RESULTHAZARD == 2 or RESULTHAZARD == 3, or RESULTHAZARD in (2, 3).

For the != operator, either several checks connected with and, or use not in with the sequence of values of interest.

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solved Returning wrong values with if in python in DEF() statement