[Solved] Inserting at the end of linked list. Why S node becoming null at each insertion

Question

s is null after every insertion because your code s = newnode is setting the local s pointer to a new value, which does not updated the contents of the original pointer in main(). You could either have insertnode() return the s pointer (e.g., s = insertnode(s,5), not recommended), or have main() create a sentinel node as a beginning-of-list placeholder that you then pass to insertnode() on the first call to it (recommended).

Accepted Answer

s is null after every insertion because your code s = newnode is setting the local s pointer to a new value, which does not updated the contents of the original pointer in main(). You could either have insertnode() return the s pointer (e.g., s = insertnode(s,5), not recommended), or have main() create a sentinel node as a beginning-of-list placeholder that you then pass to insertnode() on the first call to it (recommended).