[Solved] if imagesNamesList==[“None” for x in range(len(listOfImages)]: [closed]

Question

You are missing a closing parenthesis:

if imagesNamesList==["None" for x in range(len(listOfImages))]:
#                                                     here--^

However, you could write this code better (cleaner and more efficiently) like so:

if imagesNamesList == ["None"]*len(listOfImages):

Or, if your lists are huge, you can do as @mgilson noted:

if all(x == "None" for x in imagesNamesList) and len(imagesNamesList) == len(listOfImages):

Though this method requires more syntax, it is actually more efficient because of the short-circuiting property of all (it will stop evaluating at the first x == "None" that comes back False, if any).

Accepted Answer

You are missing a closing parenthesis:

if imagesNamesList==["None" for x in range(len(listOfImages))]:
#                                                     here--^

However, you could write this code better (cleaner and more efficiently) like so:

if imagesNamesList == ["None"]*len(listOfImages):

Or, if your lists are huge, you can do as @mgilson noted:

if all(x == "None" for x in imagesNamesList) and len(imagesNamesList) == len(listOfImages):

Though this method requires more syntax, it is actually more efficient because of the short-circuiting property of all (it will stop evaluating at the first x == "None" that comes back False, if any).