[Solved] Defining function with an argument, employs while loop and returns largest power of 2 that is less than or equal to number [closed]

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A simple while loop works, just make sure you divide the number by 2, otherwise you’ll get the NEXT power of 2.

def function(number):
    x = 1
    while x <= number:
        x *= 2
    return x / 2

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solved Defining function with an argument, employs while loop and returns largest power of 2 that is less than or equal to number [closed]