[Solved] if conditions, when i want to second argument [closed]

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Not sure if you are aware, but when you run (sorry for running on windows)

program.exe arg1 arg2

then argv[0] is program.exe, argv[1] is arg1, argv[2] is arg2, so careful what you call the 1st and 2nd argument, meaning argv[1] is indeed the first string after the binary name, but only because of C++ indexing that starts from 0.

From what you are trying to achieve there is no need for the loop and iterating over the arguments.

#include <fstream>
#include <iostream>
#include <string.h>
using namespace std;
int main(int argc, char* argv[])
{
    string s = "all";
    string t = "top";
    if (argc >= 3 && ! (argv[2] == s || argv[2] == t)) {
        cout << "INVALID MODE" << endl;
    }
}

There are plenty of questions answering parsing a string into int.

As said here though, picking up C++ beginner book is a better time investment than trying what compiles..

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solved if conditions, when i want to second argument [closed]