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No. For example, take the following grammar:
E -> TE' | T
E' -> +TE' | -TE' | T
T -> FT' | F
T' -> *FT' | /FT' | F
F -> cte | (E)
It is the well known grammar for arithmetic expressions, written in LL(1) form. It is also a well known non-regular language, since it contains a Dick language (balanced parenthesis). This is of course not a formal proof that such language is not regular, but the proof is not very difficult, using the pumping lemma, and it should be easy to find on the web.
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solved Any Language that can be generated LL1 Grammar is regular. True/False