[Solved] real-valued function in python [closed]

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Here is how you can incorporate the conditions into the function:

def f(x):
    if x <= 15:
        return x * 2 + 10
    if x <= 35:
        return 3 * x ** 2
    return 2 * x**3 - 5

When calling the function:

>>> f(31.039)
2890.2585630000003
>>> f(42.103)
149263.82765345403
>>>

For the display_f:

def f(x):
    if x <= 15:
        return x * 2 + 10
    if x <= 35:
        return 3 * x ** 2
    return 2 * x**3 - 5
number = float(input("Enter a real number: "))
num = '{:.3f}'.format(number)
display_f = f"f({num}) = {'{:.3f}'.format(round(f(number), 3))}"
print(display_f)

Output:

Enter a real number: 51.73
f(51.730) = 276853.225

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solved real-valued function in python [closed]