[Solved] Tried to solve the “Close Far” exercise [closed]

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You basically need to compare a with both b and c (using Math.abs(a-b) and using Math.abs(a-c)) and then check if the other values differ by at least 2. Something like this:

    public static boolean closeFar(int a, int b, int c) {
                return ( (Math.abs(a-b) == 1 && (Math.abs(a-c) >= 2 && Math.abs(b-c) >= 2) ||
                         (Math.abs(a-c) == 1 && (Math.abs(a-b) >= 2 && Math.abs(b-c) >= 2)))
                       );
    }

Test cases:

        System.out.println(closeFar(1,2,10)); //prints true
        System.out.println(closeFar(1,2,3)); //prints false
        System.out.println(closeFar(4,1,3)); //prints true

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solved Tried to solve the “Close Far” exercise [closed]